What is the correspondence between a float (number between 0 and 1) and a frequency ?
For example for a high pass filter :
- cut at 150 Hz = float(x.xx)
- and vice versa float(0.35) = x Hz ?
For example for a high pass filter :
- cut at 150 Hz = float(x.xx)
- and vice versa float(0.35) = x Hz ?
发表时间 Thu 22 Oct 20 @ 2:19 pm
Not sure I think it's dial² interpolated over 20Hz to 20kHz, it might even be dial³
发表时间 Thu 22 Oct 20 @ 3:06 pm
There's no fixed rule here, so depends a bit on what you're making which part of the frequency range is more important to you.
For the default filter the range is indeed cubed, but for the echo it's linear for the high pass and squared for the low pass.
For the default filter the range is indeed cubed, but for the echo it's linear for the high pass and squared for the low pass.
发表时间 Thu 22 Oct 20 @ 3:30 pm
how about the native separate filters, [something I thought about be never checked]
发表时间 Thu 22 Oct 20 @ 3:36 pm
Also cubed, but over the range of the entire knob instead of only half.
发表时间 Thu 22 Oct 20 @ 4:19 pm
I'm using a cubic mapping as well.
发表时间 Sun 25 Oct 20 @ 7:58 pm
mmmmhhh .. I don't really know how to use or enter equalizer frequencies in an effect ..
But in the program itself I have set it that way.
There it is entered in Hz
But in the program itself I have set it that way.
There it is entered in Hz
发表时间 Mon 26 Oct 20 @ 3:46 am
@djdutschi, entirely different thing.
发表时间 Mon 26 Oct 20 @ 12:51 pm
locodog wrote :
@djdutschi, entirely different thing.
That may be true. But there are also a couple of effects that access the equalizer frequencies ;-)
That's why I wrote this.
发表时间 Mon 26 Oct 20 @ 5:34 pm
I realized that my question is silly because I was taking the problem backwards.
Just determine a frequency in hertz (example 500 Hz) and use it as it is in a formula like w = 2 * PI * 500 / SampleRate
Just determine a frequency in hertz (example 500 Hz) and use it as it is in a formula like w = 2 * PI * 500 / SampleRate
发表时间 Sat 07 Nov 20 @ 10:33 am